Mock Test on Quantitative Techniques by CLATalogue
Mock Test on Quantitative Techniques by CLATalogue
Direction for Question 1-8: There are two pie charts given. In first one, the percentage breakup of no of children (under age 10) of six states is given and similarly in second pie chart, percentage breakup of number of children between 11 to 16 age is given. Also a table is attached giving the details about the boys:girls sex ratio. Answer the following questions based on above information.
Q1: What is the difference between number of boys from Karnataka (under age 10) and number of girls from Assam (between age 11 to 16)?
102135 (b) 103125 (c) 104215 (d) 105115
Q2: If each state had equal number of children up to age 16, which state would have least number of children between 10-11 yrs age?
Jharkhand (b) Assam (c) UP (d) Cannot be determined
Q3: What is the average number of girls for each state (including both the age groups)?
448895 (b) 458895 c) 448795 (d) 447895
Q4: What is the total number of boys in the given states?
3306625 (b) 3306725 (c) 3216725 (d) 3206675
Q5: Which two states have equal number of girls and in which age group?
Jharkhand & Assam in age group between 11-16
Karnataka & Gujarat in age group of under 10
Delhi & Gujarat in age group between 11-16
Gujarat and Jharkhand in age group under 10
Q6: Which state has the highest number of girls in total?
Karnataka (b) Assam (c) Delhi (d) Gujarat
Q7: Which state has the highest number of boys in age between 10-11 yrs?
Assam (b) UP (c) Gujarat (d) Jharkhand
Q 8: Which two states have equal number of boys in any age group?
Delhi & Assam (c) Karnataka & Assam
Karnataka & Delhi (d) Gujarat & Jharkhand
Q9: If Length of a rectangle is 4 times the breadth, then find the area of square whose side is equal to average of length and breadth of the rectangle if area of rectangle is 256 cm2.
225cm2 (b) 196cm2 (c) 256cm2 (d) 400cm2
Q10: In the previous question if a circle has to be made within the square such that its circumference touches the side of square, what will be the area of that square?
314cm2 (b) 209cm2 (c) 156cm2 (d) 254 cm2
Question 11-13: If Swapnil is earning interest on the principal amount of loan that he gave to Ram and Shyam @ of 15% in S.I and C.I respectively. The loan is given for 3 years. The difference between S.I and C.I is Rs.70.875. Answer the following questions.
Q11: What is the Principal amount lent by Swapnil?
1005 (b) 1000 (c) 1050 (d) 1100
Q12: What would be the difference in S.I and C.I if the same amount of money is lent to both Ram and Shyam @10% for same time?
100 (b) 75 (c) 10 (d) 31
Q13: How much Swapnil should lent to Ram (in S.I. only) in order to earn same interest as he earns from Shyam @10% for 3 yrs?
1100 (b) 1103 (c) 1200 (d) 1203
Question 14-15: Ojas owns a bookstore and makes a profit of 12.5% by selling books at certain price. His profit increases to 37.5% if he starts selling books at Rs.28 more than what he was usually charging. Answer the following question based on given information.
Q14: What was Ojas’s original selling price?
130 (b) 122 (c) 128 (d) 126
Q15: At what price Ojas purchased his books?
112 (b) 115 (c) 122 (d) 110
Answers & Solutions:
Tips for solving data set Question 1 to 8:
The data set has two pie charts and one table which give gender details ok kids. Read the questions first then as per requirement fill up the table which will include columns with boys under age 10, girls under age 10 and boys and girls between 11-16 and rows will have different states. A table with all the numbers for reference but I suggest you first read questions and fill as per requirement only not just look at the solutions.
We will also require division of 25 lakh and 35 lakh children in different states so that boys girls division can be done from that data.
The data set is vast and detailed but if done with calm mind you can score 8 marks with simple calculation. But remember to keep track of time. In exam if such a data set come first try read questions and attempt 4 easy one.
Children age < 10
Children age 11 to 16
Ans: (b) 103125
Sol: Number of Boys from Karnataka (age<10) = 93750
Number of Girls from Assam (age 11-16) = 196875
Difference between the boys from Karnataka and Girls from Assam = 196875 – 93750
Ans: (d) Cannot be determined
Sol: the question asks us to assume that all states have equal no. of children under age 16, even if we go by the assumption, the distribution of children among states under different age group is different hence out of total 60 lakh (total under age of 16) even each state with 10 lakh children, the sum of actual number of children is above 10 lakh. Hence It is not possible to answer the question with the given assumption as negative number of children is not practical situation correct answer.
Ans: (a) 448895
Sol: As total girls = 2693375 (sum of all the girls in both age groups)
Average number of girls each state = 2693375 / 6 = 448895
Ans: (a) 3306625
Sol: there is no shortcut for these calculations, you will need to calculate number of boys in each state and add the numbers to get the total.
Ans: (c) Delhi and Gujarat in age between 11-16
Sol: From table calculations we can see a lot of similar numbers but options are confusing so make sure you check all the options before marking the answer.
Ans: (c) Delhi
Sol: From the table compare the options.
Ans: (a) Assam
Sol: As the number of children has been given for age<10 and age 11-16, for number of boys between the age of 10-11 we will need to subtract no. of boys under age<10 from the no. of boys between age 11-16. From the table below we can see Assam has the highest number of boys between the age of 10-11.
Ans: (a) Delhi and Assam
Sol: Table observation.
Ans: (d) 400 cm2
Sol: Given, Length = 4* breadth (let length be l and breadth be b)
Area of rectangle = l*b = 256
=> 4*b2 = 256
b = 8 cm hence l = 8*4 = 32cm
Side of square = Average of l and b = 8+32/2 = 20cm
Area of square = 20*20 =400cm2
Ans: (a) 314 cm2
Sol: Circle has to be made under square while touching all the sides; hence radius will be half of the side of square, i.e., 10cm
Area of circle = (pi) r2 = 3.14 *10*10 = 314 cm2
Ans: (b) 1000
Sol: C.I – S.I = 70.875
P [ (1 + r/100)^t -1 ] – P*r*t /100 = 70.875
R =15%, t = 3 years, putting the values in above equation gives P = 1000
Note: In such questions one should start with the options available as it is easier to rule out options then dealing with complicated calculations.
Ans: (d) 31
Sol: Difference between SI and CI = P [ (1 + r/100)^t -1 ] – P*r*t /100
In last question P = 1000, here r = 10% and t = 3
Hence difference between CI and SI after putting in the values would be 31
Ans: (b) 1103
Sol: C.I for P = 1000, r = 10% and t = 3 = P[(1+r)^t – 1]
C.I = 331
S.I. = P*r*t / 100 (as S.I. has to be equal to C.I)
331 = P* 10*3/100
P = 1103.333
Ans: (d) 126
Sol: Profit % = 12.5 %
Let S be the selling Price and C be cost price,
(S-C)*100 / C = Profit %
S-C / C = 12.5 /100 = 0.125
S = 1.125 C
If S is increased by adding 28 then,
(S+28) –C /C = 37.5% = 0.375
C replaced by S
S + 28 =1.375 *C = 1.375*S/1.125
S = 126
Ans: (c) 112
Sol: Cost Price C = S/1.125 = 126/1.125 = 112 ( from previous question)